Practice 4 Q21
Practice 4 Q21
Find \(\displaystyle\displaystyle \displaystyle\int{\frac{1}{{{x}^{2}}\sqrt{4-{{x}^{2}}}}}\mathrm{ d}x\) using the substitution \( x=\frac{2}{u}\).
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Answer:\(-\displaystyle\frac{1}{4}\sqrt{\frac{4}{x^2}-1} + C\)
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