Techniques of Integration - Integration by Substitution
Techniques of Integration - Integration by Substitution
\(\displaystyle\displaystyle \displaystyle\int \frac{e^{-2x}}{e^{-x} + 1} dx\), let \(u = e^{-x}\).
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Answer:\(\ln \left( {{e}^{-x}}+1 \right)-{{e}^{-x}}+C\)
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