$\displaystyle\int{4{{x}^{3}}}{{({{x}^{4}}+7)}^{4}}\mathrm{d}x$ $\displaystyle\int{\frac{x+2}{{{x}^{

Question

$\displaystyle\int{4{{x}^{3}}}{{({{x}^{4}}+7)}^{4}}\mathrm{d}x$ $\displaystyle\int{\frac{x+2}{{{x}^{2}}+4x+6}}\mathrm{d}x$ $\displaystyle\int{x{{e}^{{{x}^{2}}+1}}}\mathrm{d}x$

Accepted Answer

(i) $\frac{(x^4+7)^5}{5}+C$. (ii) $\frac12\ln|x^2+4x+6|+C$. (iii) $\frac12e^{x^2+1}+C$.

Worked Example 5

Worked Example 5

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