The total surface area of a spherical ice-ball is decreasing at a rate of $2$ cm$^2$/s. Find the

Question

The total surface area of a spherical ice-ball is decreasing at a rate of $2$ cm$^2$/s. Find the rate of change of the volume when its radius is $0.5$ cm.

Accepted Answer

$\frac{\mathrm{d}V}{\mathrm{d}t}=-\frac{1}{2}\text{ cm}^3\text{ s}^{-1}$

Differentiation - Connected Rates of Change

Differentiation - Connected Rates of Change

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