Differentiation - Tangents and Normals at a Point

Differentiation - Tangents and Normals at a Point

The equation of a curve is \(y=a\sqrt{2x+1}+b\), where \(a\) and \(b\) are constants. The equation of the normal to the curve at the point where \(x=4\) is \(2y+3x=20\). Find the value of \(a\) and of \(b\).
.

Video Solution:

Video Solution

Video solution locked

A free account saves your progress; this video needs a course plan.

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs a course plan.

Answer:\(a=2\), \(b=-2\)

Need help? Join our A-Maths tuition classes.

Learn more