Techniques of Differentiation - Implicit Differentiation

Techniques of Differentiation - Implicit Differentiation

Given the following relations between \(x\) and \(y\), find \(\frac{\mathrm{d}y}{\mathrm{d}x}\) in terms of \(x\) and \(y\).

  1. \({{y}^{x}}=y+x\)
  2. \(y={{x}^{\text{sec}\hspace{0.5em}x}}\)
  3. \(y={{x}^{{{x}^{2}}}}\)

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Answer:(a) \(\frac{y[1-(y+x)\ln y]}{x(y+x)-y}\) (b) \(\frac{y\sec x(1+x\tan x\ln x)}{x}\) (c) \(x^{x^2+1}(1+2\ln x)\)

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