Find the equation of the tangent and the normal to the curve $y=\frac{x-3}{x+1}$ at the point wher

Question

Find the equation of the tangent and the normal to the curve $y=\frac{x-3}{x+1}$ at the point where $y=-1$.

Accepted Answer

Tangent: $y=x-2$, normal: $y=-x$

Differentiation