A curve has parametric equations given by $x = 2\ln(\sin \theta)$ and \(y = \frac{\cos 2\theta}{2}

Question

A curve has parametric equations given by $x = 2\ln(\sin \theta)$ and $y = \frac{\cos 2\theta}{2}$. Show that $\frac{\mathrm{d}y}{\mathrm{d}x} = -\sin^{2}\theta$.

Accepted Answer

$\frac{\mathrm dy}{\mathrm dx}=-\sin^2\theta$

Techniques of Differentiation - Differentiation of Parametric Equations

Techniques of Differentiation - Differentiation of Parametric Equations

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