It is given that $y = 3^{(x^{2} + 2x)}$. Show that \(\frac{\mathrm{d}^{2}y}{\mathrm{d}x^

Question

It is given that $y = 3^{(x^{2} + 2x)}$. Show that $\frac{\mathrm{d}^{2}y}{\mathrm{d}x^{2}} = \frac{1}{y}\left(\frac{\mathrm{d}y}{\mathrm{d}x}\right)^{2} + 2y\ln 3$.

Accepted Answer

$\frac{\mathrm d^2y}{\mathrm dx^2}=\frac1y\left(\frac{\mathrm dy}{\mathrm dx}\right)^2+2y\ln3$

Techniques of Differentiation - Second and Higher Derivatives

Techniques of Differentiation - Second and Higher Derivatives

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