The roots of the equation $x^3-6x^2+11x-6=0$ are $\alpha$, $\beta$ and $\gamma$. Write down

Question

The roots of the equation $x^3-6x^2+11x-6=0$ are $\alpha$, $\beta$ and $\gamma$. Write down the values of $\alpha+\beta+\gamma$, $\alpha\beta+\beta\gamma+\gamma\alpha$ and $\alpha\beta\gamma$.

Accepted Answer

$6,\ 11,\ 6$

Symmetric values from a cubic

Symmetric values from a cubic

Solution:

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