In the diagram, $ABC$ is a right-angled triangle in which $\angle BAC=90{}^\circ $. $AC=16$ cm

Question

In the diagram, $ABC$ is a right-angled triangle in which $\angle BAC=90{}^\circ $. $AC=16$ cm, $BC=20$ cm, $AB$ is produced to $P$ and $AC$ is produced to $Q$. Calculate $\angle ABC$, correct to $1$ decimal place. Express each of the following as a fraction, in its simplest form. $\sin \angle BCA$, $\cos \angle BCQ$.

Accepted Answer

(a) $53.1^\circ$ (b)(i) $\frac{3}{5}$ (ii) $-\frac{4}{5}$

Supplementary Angle Identities: Analyzing Trigonometry Beyond \(90^\circ\)

Supplementary Angle Identities: Analyzing Trigonometry Beyond \(90^\circ\)

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