You can already solve a quadratic equation by factorising, completing the square or using the formula. This chapter turns the question around: without solving \(ax^2+bx+c=0\), what do its roots \(\alpha\) and \(\beta\) tell us about the coefficients \(a\), \(b\) and \(c\)?
Sum and product of roots of \(ax^2+bx+c=0\), \(a\ne 0\)
| Result | Formula | Example: \(2x^2-8x+6=0\) |
|---|---|---|
| Sum of roots | \(\alpha+\beta=-\dfrac{b}{a}\) | \(\alpha+\beta=-\dfrac{-8}{2}=4\) |
| Product of roots | \(\alpha\beta=\dfrac{c}{a}\) | \(\alpha\beta=\dfrac{6}{2}=3\) |
Both results come from comparing coefficients: dividing by \(a\) and factorising gives \(x^2+\dfrac{b}{a}x+\dfrac{c}{a}=(x-\alpha)(x-\beta)=x^2-(\alpha+\beta)x+\alpha\beta\).
Building a quadratic from its roots
Reversing the comparison, a quadratic equation with roots \(\alpha\) and \(\beta\) is \(x^2-(\alpha+\beta)x+\alpha\beta=0\), that is, \(x^2-(\text{sum of roots})\,x+(\text{product of roots})=0\).
Rearrange into the form \(ax^2+bx+c=0\) before reading off \(a\), \(b\) and \(c\) — signs included. The sum of roots carries a negative sign: \(\alpha+\beta=-\frac{b}{a}\).
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