Solving a hundred-pupil frequency table
Solving a hundred-pupil frequency table
Secondary 2
7 marks
TGM Original Questions
Core stretch
Study hours 3, 4, 5, 6 have frequencies \(42,x,y,18\) for 100 pupils. The mean is 4.3.
- Form two equations and solve for \(x,y\).[4]
- State the mode and median.[2]
- A pupil claims more than one quarter studied 5 hours. Is the claim correct?[1]
Solution:
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Answer:(a) \(x+y=40,\ 4x+5y=196\), so \(x=4,y=36\). (b) Mode 3, median 5. (c) Yes, \(36\%>25\%\).
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