A fisherman catches \(200\) fish to sell. He measures the lengths, \(l\) cm of these fish, and the results are shown in the frequency table below.
| Length \(l\) cm | \(0 \leq l \leq 10\) | \(10 \leq l \leq 20\) | \(20 \leq l \leq 30\) | \(30 \leq l \leq 40\) | \(40 \leq l \leq 60\) | \(60 \leq l \leq 75\) | \(75 \leq l \leq 100\) |
|---|---|---|---|---|---|---|---|
| Frequency | \(30\) | \(40\) | \(50\) | \(30\) | \(33\) | \(11\) | \(6\) |
Calculate an estimate for the standard deviation of the lengths of the fish.
[3]A cumulative frequency diagram is given below for the lengths of the fish.

Use the graph to answer the following.
Estimate the interquartile range.
Given that \(40\%\) of the fish have a length more than \(k\) cm, find the value of \(k\).
[6]In order to sell the fish, the fisherman classifies them as small, medium or large.
\(\quad\)Small fish have a length less than \(20\) cm.
\(\quad\)Medium fish have a length greater than or equal to \(20\) cm but less than \(60\) cm.
\(\quad\)Large fish have a length greater than or equal to \(60\) cm.
Write down the probability that a fish is small.
[2]The cost of a small fish is \(\$4\), a medium fish \(\$10\), and a large fish \(\$12\).
Copy and complete the following table, which gives a probability distribution for the cost \(\$X\).
[2]| Cost \(\$X\) | \(4\) | \(10\) | \(12\) |
|---|---|---|---|
| \(P(X = x)\) | \(0.565\) |
Find E(X).
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