A curve is given by $x=t^2+1$, $y=t^3-3t$. Find $\frac{\mathrm dy}{\mathrm dx}$ for $t\ne0$,

Question

A curve is given by $x=t^2+1$, $y=t^3-3t$. Find $\frac{\mathrm dy}{\mathrm dx}$ for $t\ne0$, and hence find its stationary points.

Accepted Answer

$\frac{3(t^2-1)}{2t};\ (2,2),\ (2,-2)$

Stationary points of a parametric curve