The roots of the equation $3{{x}^{2}}-3kx+k-6=0$ are $\alpha $ and $\beta $. If \({{\alpha }^{

Question

The roots of the equation $3{{x}^{2}}-3kx+k-6=0$ are $\alpha $ and $\beta $. If ${{\alpha }^{2}}+{{\beta }^{2}}=\frac{20}{3}$, find the possible values of $k$.

Accepted Answer

$k=2$ or $k=-\frac43$.

Solving for an Unknown in Quadratic Equation

Solving for an Unknown in Quadratic Equation

Solution:

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