Solve ${{3}^{x}}=81$ ${{\left( \frac{1}{8} \right)}^{x}}=16$ ${{10}^{-x}}=0.001$ \({{3}^{2x-1}

Question

Solve ${{3}^{x}}=81$ ${{\left( \frac{1}{8} \right)}^{x}}=16$ ${{10}^{-x}}=0.001$ ${{3}^{2x-1}}=243$ ${{2}^{x+3}}\times {{4}^{x}}={{8}^{3x-2}}$ ${{5}^{14}}\div \frac{1}{25}={{5}^{x}}$

Accepted Answer

(i) $x=4$. (ii) $x=-\frac43$. (iii) $x=3$. (iv) $x=3$. (v) $x=\frac32$. (vi) $x=16$.

Solving Exponential Equations Using Index Laws

Solving Exponential Equations Using Index Laws

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