A boat travelling with and against a current

A boat travelling with and against a current

IP 1
7 marks

A boat travels \(36\text{ km}\) downstream in \(2\) hours and returns the same \(36\text{ km}\) upstream in \(3\) hours. Assume the boat's speed in still water, \(b\text{ km/h}\), and the speed of the current, \(c\text{ km/h}\), are constant.

  1. Explain why the downstream speed is \((b+c)\text{ km/h}\), and form two equations in \(b\) and \(c\).[2]
  2. Find \(b\) and \(c\).[2]
  3. On another day the current is twice as fast. Find the time for the upstream journey, and state one assumption you have made.[2]
  4. Explain why the model fails if the current is \(15\text{ km/h}\) or faster.[1]

Solution:

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Answer:(a) \(b+c=18\), \(b-c=12\) (b) \(b=15\), \(c=3\) (c) \(4\) hours, assuming the boat's still-water speed is unchanged (d) upstream speed \(15-c\le0\)

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