A bag contains \(x\) red counters and \(y\) blue counters.
When \(5\) more red counters are placed in the bag, the number of red counters becomes equal to the number of blue counters.
The bag originally contains \(35\) counters altogether.
Form two simultaneous equations in \(x\) and \(y\).
[2]Hence, find the original number of red counters and blue counters.
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