In the diagram, $ABC$ is a triangle. $E$ is the point on $BC$ such that \(\angle ABC = \a

Question

In the diagram, $ABC$ is a triangle. $E$ is the point on $BC$ such that $\angle ABC = \angle EDC$. Show that triangles $ABC$ and $EDC$ are similar. Given that $AB = 5x$, $BC = 3y$, $DE = 2$ and $CD = 4$. Find the ratio of $x : y$.

Accepted Answer

$\text{(i)}\ \triangle ABC\sim\triangle EDC\text{ (AA)}$ $\text{(ii)}\ x:y=3:10$

Similarity Criteria in Nested Triangles: Analysis of AA and SAS Postulates

Similarity Criteria in Nested Triangles: Analysis of AA and SAS Postulates

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