Sideways parabola cut by a vertical line
Sideways parabola cut by a vertical line
Secondary 4
5 marks
Original parallel to supplied A Math Applications of Integration references
The line \(x=1\) meets the curve \(x=\dfrac{(y-2)^2}{4}\) at \(P\) and \(Q\).
Find the area enclosed by the curve and the line.[5]
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Answer:\(\dfrac83\text{ units}^2\)
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