The curve $x=(y-2)^2$ intersects the line $x=4-y$ at the points $P$ and $Q$. Find the coordi

Question

The curve $x=(y-2)^2$ intersects the line $x=4-y$ at the points $P$ and $Q$. Find the coordinates of $P$ and $Q$.[3] Hence find the area enclosed by the curve and the line.[5]

Accepted Answer

(i) $P=(4,0)$, $Q=(1,3)$ (ii) $\dfrac92\text{ units}^2$

Sideways parabola and an oblique line

Sideways parabola and an oblique line

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