Showing a line never meets a curve for any value of a constant
Showing a line never meets a curve for any value of a constant
Secondary 3
Show that the line \(y=4-kx-k^2\) never meets the curve \(y=x^2+5\), whatever the value of the constant \(k\).
Solution:
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Answer:Shown: \(x^2+kx+k^2+1=0\) has \(D=-3k^2-4<0\) for every \(k\).
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