Tim Gan Math
Sign up free

Second derivatives

Second derivatives

4 marks
TGM Original
Given y=2 sqrt(x) + 1x, x>0, find dydx and d2ydx2. Hence find the value of the second derivative at x=1.

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs tuition enrolment.

Create free accountSign inMath tuition

Create a free account to practise similar questions.

Create free accountSign inMath tuition
Answer:\(\dfrac{\mathrm{d}y}{\mathrm{d}x}=- \dfrac{1}{x^{2}} + \dfrac{1}{\sqrt{x}}\); \(\dfrac{\mathrm{d}^2y}{\mathrm{d}x^2}=\dfrac{2}{x^{3}} - \dfrac{1}{2 x^{\frac{3}{2}}}\); at \(x=1\), \(\dfrac{3}{2}\).

Need help? Join our JC Math tuition classes.

Learn more