Sec 3/4 E Math T11-Q14 - Opposite angles of a cyclic quadrilateral

Sec 3/4 E Math T11-Q14 - Opposite angles of a cyclic quadrilateral

Secondary 3
Original parallel to Sec3&4 E Math FA

The points \(P\), \(Q\), \(R\) and \(S\) lie on a circle. \(\angle PQR=72^\circ\). Find \(\angle PSR\), giving a geometrical reason.

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Answer:\(108^\circ\), because opposite angles of a cyclic quadrilateral sum to \(180^\circ\).

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