Sec 3/4 E Math T01-Q31 - Completing the square and solving a quadratic equation

Sec 3/4 E Math T01-Q31 - Completing the square and solving a quadratic equation

Secondary 3
Original parallel to Sec3&4 E Math FA

Consider the expression \(x^2-6x+3\).

  1. Express \(x^2-6x+3\) in the form \((x-a)^2-b\).
  2. Hence, solve \(x^2-6x+3=0\), giving your answers correct to 2 decimal places.

Solution:

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Answer:(a) \((x-3)^2-6\); (b) \(x=0.55\) or \(x=5.45\).

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