Sec 3/4 E Math T01-Q25 - Completing the square and solving a quadratic equation
Sec 3/4 E Math T01-Q25 - Completing the square and solving a quadratic equation
Secondary 3
Original parallel to Sec3&4 E Math FA
Consider the expression \(x^2-4x-3\).
- Express \(x^2-4x-3\) in the form \((x-a)^2-b\).
- Hence, solve \(x^2-4x-3=0\), giving your answers correct to 2 decimal places.
Video Solution:
Video solution locked
Solution:
Solution locked
Sign in to view the step-by-step solution
Similar questions are unavailable for this question.
Answer:(a) \((x-2)^2-7\); (b) \(x=-0.65\) or \(x=4.65\).
Need help? Join our JC Math tuition classes.
Learn more