Sec 3/4 E Math T01-Q19 - Completing the square and solving a quadratic equation

Sec 3/4 E Math T01-Q19 - Completing the square and solving a quadratic equation

Secondary 3
Original parallel to Sec3&4 E Math FA

Consider the expression \(x^2-12x+28\).

  1. Express \(x^2-12x+28\) in the form \((x-a)^2-b\).
  2. Hence, solve \(x^2-12x+28=0\), giving your answers correct to 2 decimal places.

Solution:

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Answer:(a) \((x-6)^2-8\); (b) \(x=3.17\) or \(x=8.83\).

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