A right triangle joined to an isosceles triangle

A right triangle joined to an isosceles triangle

Secondary 2
TGM Original Questions

Triangle \(ABD\) is right-angled at \(B\), with \(AB=15\) cm and \(AD=17\) cm. Triangle \(BCD\) is isosceles with \(BC=CD=10\) cm. Find

  1. \(BD\),
  2. \(\sin\angle ADB\),
  3. the area of \(\triangle BCD\). Give non-exact lengths, areas and other numerical values to 3 significant figures, and angles to 1 decimal place, unless otherwise stated.

Solution:

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Answer:(a) \(8\) cm; (b) \(15/17\); (c) \(8\sqrt{21}\approx36.7\text{ cm}^2\).

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