Exact ratios in a Pythagorean triangle

Exact ratios in a Pythagorean triangle

Secondary 2
TGM Original Questions

Triangle \(ABC\) is right-angled at \(C\), with \(AB=25\) cm and \(BC=15\) cm. Point \(D\) lies on \(AC\), where \(CD=8\) cm. Without a calculator, find

  1. \(BD\),
  2. \(\tan\angle CDB\),
  3. \(\cos\angle CAB\).

Solution:

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Answer:(a) \(17\) cm; (b) \(15/8\); (c) \(4/5\).

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