Parameter and tangency from a graph

Parameter and tangency from a graph

Secondary 2
TGM Original Questions

The graph of \(y=x^2+4x+a\) shown has roots \(-5\) and \(1\).

  1. State its line of symmetry.
  2. Find \(a\).
  3. The line \(y=-8\) meets the graph twice; find the two points of intersection.
  4. Find \(h\) such that \(x^2+4x-5=h\) has exactly one real solution.

Solution:

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Answer:(a) \(x=-2\); (b) \(a=-5\); (c) \((-3,-8),(-1,-8)\); (d) \(h=-9\).

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