Quadratic and line intersection by graph

Quadratic and line intersection by graph

Secondary 2
TGM Original Questions

For \(y=x^2-2x-8\):

  1. complete the missing table values \(a,b\)
  2. draw the graph for \(-3\le x\le5\)
  3. use it to
    1. find \(x\) when \(y=-8\), and
    2. solve \(x^2-2x-8=x+2\) by drawing the line \(y=x+2\).
\(x\)-\(3\)-\(2\)-\(1\)\(0\)\(1\)\(2\)\(3\)\(4\)\(5\)
\(y\)\(7\)\(0\)\(a\)-\(8\)-\(9\)-\(8\)-\(5\)\(b\)\(7\)

Solution:

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Answer:(a) \(a=-5,b=0\); (c)(i) \(x=0,2\); (ii) \(x=-2,5\).

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