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Perfect-square ratios
Secondary 2
TGM Original Questions
Given \(9x^2-24xy+16y^2=0\), find \(\frac{x}{y}\), where \(y\ne0\).
Given \(9p^2+16q^2=24pq\), find the ratio \(p:q\), where \(q\ne0\).
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Answer:
(a) \(\frac{x}{y}=\frac43\); (b) \(p:q=4:3\).
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