Two graphs from value tables

Two graphs from value tables

Secondary 2
TGM Original Questions

For \(y=x^2+4x-5\):

  1. find the missing table value \(p\)
  2. plot it for \(-6\le x\le2\)
  3. estimate
    1. \(y\) at \(x=-4.5\),
    2. \(x\) when \(y=-4\), and
    3. the least value.
    1. plot \(y=-x-1\) using its table
    2. solve the intersection equation.
\(x\)-\(6\)-\(5\)-\(4\)-\(3\)-\(2\)-\(1\)\(0\)\(1\)\(2\)
\(y\)\(7\)\(0\)-\(5\)\(p\)-\(9\)-\(8\)-\(5\)\(0\)\(7\)
\(x\)-\(6\)-\(2\)\(2\)
\(y=-x-1\)\(5\)\(1\)-\(3\)

Solution:

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Answer:(a) \(p=-8\); (c)(i) \(-2.75\); (ii) \(x\approx-4.24,0.24\); (iii) \(-9\); (d)(ii) \(x\approx-5.70,0.70\).

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