Multi-person age equation

Multi-person age equation

Secondary 2
TGM Original Questions

On 1 January 2022, Alex was \(x\), Bea was \(8\) years older, and Chen was twice Alex’s age.

  1. Give Bea’s and Chen’s ages then.
  2. Give all three ages four years later.
  3. Chen’s later age times Alex’s later age equals the square of Bea’s 2022 age; show \(x^2-4x-48=0\).
  4. Solve it.
  5. Find Chen’s age in 2026.

Solution:

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Answer:(i) \(x+8,2x\); (ii) \(x+4,x+12,2x+4\); (iv) \(x=8\); (v) \(20\) years.

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