Parabola-line graph interpretation

Parabola-line graph interpretation

Secondary 2
TGM Original Questions

The graphs \(y=x^2-4x-5\) and \(y=2x-5\) are shown.

  1. Find their intersection points.
  2. From the graph estimate solutions of
    1. \(x^2-4x-5=0\), and
    2. \(x^2-4x=4\).
  3. State the parabola’s symmetry line.
  4. Explain for which \(k\) the equation \(x^2-4x-5=k\) has no real solution.

Solution:

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Answer:(a) \((0,-5),(6,7)\); (b)(i) \(x=-1,5\); (ii) \(x\approx-0.83,4.83\); (c) \(x=2\); (d) \(k<-9\).

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