Converse proof at a rectangle diagonal

Converse proof at a rectangle diagonal

Secondary 2
TGM Original Questions

Rectangle \(ABCD\) has \(AB=20\) cm and \(BC=15\) cm. Point \(E\) lies on diagonal \(BD\) with \(BE:ED=9:16\), and \(CE=12\) cm.

  1. Show that \(CE\perp BD\).
  2. Find the area of \(\triangle ECD\).

Solution:

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Answer:(a) proved; (b) \(96\text{ cm}^2\).

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