A midpoint-projection Pythagorean identity

A midpoint-projection Pythagorean identity

Secondary 2
TGM Original Questions

Triangle \(RST\) is right-angled at \(S\). Point \(M\) is the midpoint of \(ST\), and \(MN\perp RT\). Prove that \(TN^2+RS^2=RN^2\).

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Answer:\(TN^2+RS^2=RN^2\), as required.

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