A biased five-sided spinner

A biased five-sided spinner

Secondary 2
TGM Original Questions

A biased spinner has the table:

Number\(1\)\(2\)\(3\)\(4\)\(5\)
Probability\(1/4\)\(x\)\(1/5\)\(1/10\)\(x\)
  1. Find \(x\).
  2. Find the probability of
    1. 2 or 3,
    2. an odd number,
    3. a number not more than 4.
  3. In 80 spins, find the expected number of results equal to 3 or 4.

Solution:

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Answer:(a) \(x=9/40\); (b)(i) \(17/40\); (ii) \(27/40\); (iii) \(31/40\); (c) \(24\).

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