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Inverse-root difference and scale change
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Inverse-root difference and scale change
Secondary 2
TGM Original Questions
The quantity \(y\) varies inversely with \(\sqrt{x}\). The difference between its values at \(x=9\) and \(x=16\) is \(5\). Find \(x\) when \(y=10\).
The quantity \(v\) is inversely proportional to \(x^2\). If \(x\) is multiplied by \(4\), find the percentage change in \(v\).
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Answer:
(a) \(x=36\); (b) \(93.75\%\) decrease.
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