Determining a direct square relation

Determining a direct square relation

Secondary 2
TGM Original Questions

The quantity \(y\) is directly proportional to \(x^2\), and the sum of its values at \(x=1\) and \(x=2\) is \(20\).

  1. Express \(y\) in terms of \(x\).
  2. Find \(y\) when \(x=-3\).

Solution:

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Answer:(a) \(y=4x^2\); (b) \(y=36\).

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