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Falling distance and magnet force
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Falling distance and magnet force
Secondary 2
TGM Original Questions
The distance \(d\) metres of an object above the ground varies directly with \((t-18)^2\), where \(t\) is seconds. Given \(d=45\) at \(t=3\), find
the formula connecting \(d,t\), and
when it reaches the ground.
A magnet force is inversely proportional to the square of distance. It is \(18\) N at one distance. Find it when the distance is tripled.
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Answer:
(a)(i) \(d=\frac15(t-18)^2\); (ii) \(18\) s; (b) \(2\) N.
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