In \(\triangle ABC\), \(P\) lies on \(AC\), \(R\) lies on \(AB\), and \(PR\parallel CB\). Given \(CP=8\) cm, \(PA=4\) cm, \(AR=6\) cm and \(BC=16\) cm:
state \(AC:AP\)
find
\(PR\), and
\(RB\).
Solution:
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Answer:(a) \(3:1\); (b)(i) \(16/3\) cm; (ii) \(12\) cm.