Height division in a trapezium

Height division in a trapezium

Secondary 2
TGM Original Questions

In trapezium \(ABCD\), \(AB\parallel CD\), \(AB=15\) cm, \(CD=9\) cm, and \(EF\) is its perpendicular height. Diagonals meet at \(X\).

  1. Name two similar triangles.
  2. If the trapezium area is \(144\text{ cm}^2\), find \(FX\).

Solution:

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Answer:(a) \(\triangle AXB\sim\triangle CXD\); (b) \(4.5\) cm.

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