Comparing plant prices

Comparing plant prices

Secondary 2
TGM Original Questions

A rose and an orchid together cost \(\$24\). A gardener buys orchids for \(\$48\). If she buys roses instead and spends \(\$72\), she gets two more plants. Let an orchid cost \($p\).

  1. Write the number of orchids.
  2. Write the number of roses.
  3. Form an equation and show that \(p^2+36p-576=0\).
  4. Solve for \(p\).
  5. Explain the rejected root.
  6. Find the number of roses.

Solution:

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Answer:(a) \(\frac{48}{p}\); (b) \(\frac{72}{24-p}\); (d) \(p=12\); (e) reject \(-48\) because a price is positive; (f) \(6\) roses.

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