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Rearranging powers and reciprocals
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Rearranging powers and reciprocals
Secondary 2
TGM Original Questions
Make \(d\) the subject of \(b=\frac{kd^3-e}{3}\).
Given \(\frac3p=\frac2q+\frac5r\), express \(q\) in terms of \(p,r\).
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Answer:
(a) \(d=\sqrt[3]{\frac{3b+e}{k}}\); (b) \(q=\frac{2pr}{3r-5p}\).
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