Scalar Multiple \(\frac{\mathrm{d}}{\mathrm{d}x}(kx^n) = k\frac{\mathrm{d}}{\mathrm{d}x}(x^n) = knx^

Question

Scalar Multiple $\frac{\mathrm{d}}{\mathrm{d}x}(kx^n) = k\frac{\mathrm{d}}{\mathrm{d}x}(x^n) = knx^{n-1}$, where $k$ is a constant. Find the derivative of each of the following, $y = 4\sqrt{x}$ $\mathrm{f}(x) = -\frac{2}{x^5}$ $\mathrm{f}(x) = -\frac{3x^2}{\sqrt{x^5}}$

Accepted Answer

(a) $\frac{2}{\sqrt{x}}$ (b) $10x^{-6}$ (c) $\frac{3}{2}x^{-\frac{3}{2}}$

Scalar Multiple

Scalar Multiple

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