The roots of the equation $2x^4-4x^3-5x^2+6x-10=0$ are $\alpha$, $\beta$, $\gamma$ and \(\de

Question

The roots of the equation $2x^4-4x^3-5x^2+6x-10=0$ are $\alpha$, $\beta$, $\gamma$ and $\delta$. Write down the values of $\sum\alpha$, $\sum\alpha\beta$, $\sum\alpha\beta\gamma$ and $\alpha\beta\gamma\delta$. Hence find the value of $\alpha^2+\beta^2+\gamma^2+\delta^2$.

Accepted Answer

(a) $2,\ -\frac{5}{2},\ -3,\ -5$ (b) $9$

Root sums and products of a quartic

Root sums and products of a quartic

Video Solution:

Solution:

Solution locked