Reflecting a logarithmic asymptote

Reflecting a logarithmic asymptote

6 marks
TGM Original
Let h(x)=ln(x+2), x>-2. Sketch h and its inverse on equal-scale axes with y=x, labelling their intercepts and asymptotes.

Solution:

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Answer:\(\mathrm h^{-1}(x)=\mathrm e^x-2\); intercepts \((-1,0),(0,\ln2)\) reflect to \((0,-1),(\ln2,0)\); asymptotes \(x=-2,y=-2\).

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