Sum of Squares

Sum of Squares

IB Year 5 | Grade 11

Prove by mathematical induction that \(\displaystyle\sum_{r=1}^{n}r^2=\dfrac{n(n+1)(2n+1)}{6}\) for every \(n\in\mathbb Z^+\).

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Answer:\(\displaystyle\sum_{r=1}^{n}r^2=\dfrac{n(n+1)(2n+1)}6\)

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